Question

Can someone help me please

A 70.0 g piece of metal wire is heated, and the temperature of the wire changes from 58.0°C to 152.0°C. The amount of heat absorbed is 972 Joules. What is the specific heat of the metal wire?

a 0.148 J/gC
b 6.77 J/gC
c 724 J/gC
d 0.0913 J/gC

Answer 1

Hi there!

`\large\boxed{\text{A. 0.148J/gC}}`

the equation q = mcΔT, where:

q = Energy (J)

cΔ = temperature change

m = mass of object

T = specific heat

Rearrange the equation to solve for the specific heat:

q/mcΔ = T

Plug in the given energy, mass, and temperature change to solve:

972 / (70 · (152 - 58)) = T

Simplify and solve:

972 / (70 · 94) = T

T = 972 / 6580 = 0.148 J/gC.