Question

For each equation, identify the acid, the base, the conjugate base, and the conjugate acid. Complete the table by filling in each empty space.

Answer 1

Hi do not know the answer sorry for the day

Answer 2

Equation:
`HCIO_(2) + H_(2)O` →
`HCIO_(2) + H_(3)O`

Acid -
`HCIO_(2)`

Base -
`H_(2)O`

Conjugate Base -
`HCIO_(2)^(-)`

Conjugate Acid -
`H_(3)O^(+)`

Equation:
`HCl + NH_(3)` →
`NH_(4)^(+) + Cl^(-)`

Acid -
`HCl`

Base -
`NH_(3)`

Conjugate Base -
`Cl^(-)`

Conjugate Acid -
`NH_(4) ^(+)`

In the first equation,
`HCIO_(2)` is the acid because it donates a proton (
`H^(+)`) to
`H_(2)O`.
`H_(2)O` is the base because it accepts the proton.
`HCIO_(2)^(-)` is the conjugate base of
`HCIO_(2)` because it is formed when
`HCIO_(2)` loses a proton.
`H_(3)O^(+)` is the conjugate acid of
`H_(2)O` because it is formed when
`H_(2)O` gains a proton.

In the second equation,
`HCl` is the acid because it donates a proton to
`NH_(3)`.
`NH_(3)` is the base because it accepts the proton.
`Cl^(-)` is the conjugate base of
`HCl` because it is formed when
`HCl` loses a proton.
`NH_(4)^(+)` is the conjugate acid of
`NH_(3)` because it is formed when
`NH_(3)` gains a proton.

The concept of conjugate acids and bases is illustrated in this table.