Answer:
(32+3+3)−1(2+2+3)(3x^{2}+3x+3)-1(x^{2}+2x+3)
(3x2+3x+3)−1(x2+2x+3)
Simplify
1
Distribute
(32+3+3)−1(2+2+3)(32+3+3)−12−2−32
Eliminate redundant parentheses
(323+3)−12−2−332+3+3−12−2−33
Subtract the numbers
32+3+3−2−2−332+3−12−24
Combine like terms
32+3−12−222+3−25
Combine like terms
22+3−222+16
Multiply by 1
Solution
22+