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Given the function h(x)=-x^2+4x+12, determine the average rate of change of the function over the interval −2≤x≤4.

User Sederqvist
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1 Answer

2 votes

Answer:

2

Explanation:

The average rate of change of h(x) in the closed interval [ a, b ] is


(f(b) - f(a))/(b-a)

Here [ a, b ] = [ - 2, 4 ] , then

f(b) = f(4) = - (4)² + 4(4) + 12 = - 16 + 16 + 12 = 12

f(a) = f(- 2) = - (- 2)² + 4(- 2) + 12 = - 4 - 8 + 12 = 0

Then

average rate of change =
(12-0)/(4-(-2)) =
(12)/(6) = 2

User Mani Jagadeesan
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