Answer:x=4 y=3
Explanation:
Let's solve your system by substitution.
2x−1=y+4;3y+1=3x−2
Step: Solve2x−1=y+4for y:
2x−1=y+4
2x−1+−y=y+4+−y(Add -y to both sides)
2x−y−1=4
2x−y−1+−2x=4+−2x(Add -2x to both sides)
−y−1=−2x+4
−y−1+1=−2x+4+1(Add 1 to both sides)
−y=−2x+5
−y
−1
=
−2x+5
−1
(Divide both sides by -1)
y=2x−5
Step: Substitute2x−5foryin3y+1=3x−2:
3y+1=3x−2
3(2x−5)+1=3x−2
6x−14=3x−2(Simplify both sides of the equation)
6x−14+−3x=3x−2+−3x(Add -3x to both sides)
3x−14=−2
3x−14+14=−2+14(Add 14 to both sides)
3x=12
3x
3
=
12
3
(Divide both sides by 3)
x=4
Step: Substitute4forxiny=2x−5:
y=2x−5
y=(2)(4)−5
y=3(Simplify both sides of the equation)