Question

You have to prepare some 2 M solutions, with 10 g of solute in each. What volume of solution will you prepare, for each solute below? (Ar:H51,Li57,N514,O516,Mg524,S532.)

a lithium sulfate, Li2SO4

Answer 1

To prepare a 2 M solution of lithium sulfate, Li2SO4, with 10 g of solute, calculate the number of moles of lithium sulfate. Use the molarity formula to find the volume of solution needed.

Step-by-step explanation:

To prepare a 2 M solution of lithium sulfate, Li2SO4, with 10 g of solute, you need to calculate the number of moles of lithium sulfate. The molar mass of Li2SO4 is 109.946 g/mol. To find the number of moles, divide the mass of the solute (10 g) by the molar mass (109.946 g/mol). This will give you the number of moles of solute.

Next, use the molarity formula:

Molarity (M) = moles of solute / volume of solution (in L)

Since you want to make a 2 M solution with 10 g of solute, you can rearrange the formula to solve for the volume:

Volume of solution (in L) = moles of solute / molarity (M)

Substituting the values you found into the formula, you can calculate the volume of solution needed.

Let me know if I can help you with anything else.

Answer 2

0.045 L or 45 mL

Step-by-step explanation:

Moles = Mass/M.Mass

Moles = 10 g / 109.94 g/mol

Moles = 0.09 moles

Also,

Molarity = Moles / Vol in L

Or,

Vol in L = Moles / Molarity

Vol in L = 0.09 mol / 2 mol/L

Vol in L = 0.045 L