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Triangle with base 18 in. and height 13 in what is the area of the triangle

User Papalagi
by
7.9k points

2 Answers

3 votes

Answer:

the area is 117in^2

:
A=(h_(b) b)/(2)=(13*18)/(2)=117^2

User Justin Abrahms
by
8.9k points
2 votes

Answer:A=117

Step-by-step explanation:A=
(h b)/(2) =(13.18)/(2)=117

User Dimgold
by
7.8k points

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