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Z2 + (2j – 3)z + (5 – j) = 0
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Z2 + (2j – 3)z + (5 – j) = 0

User Juan Tomas
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1 Answer

5 votes

Answer:

2z+(2j-3)z+(5-j)=0

2z +2jz-3z+5-j=0

2z-3z+2jz-j=-5

-z+2jz-j=-5

2jz-z-j=-5

I hope this help

User Serg Hospodarets
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