Answer:
The porter charges Rs 300 at this rate.
Explanation:
We solve this question by proportions, using rule of three.
75 Rs - 4 km - 50 kg
x Rs - 10 km - 80 kg
Relationship between the variables:
As the distance, or the weight increase, the rate will increase. This means that:
![(75)/(x) = (4*50)/(10*80)](https://img.qammunity.org/2022/formulas/mathematics/college/6x344r5bsllrccaro0vbht0xe88w6qpie1.png)
![(75)/(x) = (200)/(800)](https://img.qammunity.org/2022/formulas/mathematics/college/s56idpxcnpgkqe0yeug6qxp4ii1cjp235g.png)
![(75)/(x) = (2)/(8)](https://img.qammunity.org/2022/formulas/mathematics/college/veerkdc3v6jysqa7de51e1fbrmbl0tx0v4.png)
![x = (75*8)/(2) = 75*4 = 300](https://img.qammunity.org/2022/formulas/mathematics/college/brg2xzm0lqc2yonc12wtldzj7tlxuou4qk.png)
The porter charges Rs 300 at this rate.