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8 votes
PhotoMath isn’t helping please help

PhotoMath isn’t helping please help-example-1

2 Answers

11 votes

Answer:

a = 15, b = 7, c = 4

Explanation:

Here's some facts that help with such tasks:


(x^y)^z = x^(y\cdot z)\\\\\sqrt[y]{x} = x^{(1)/(y)}\\\\\sqrt[y]{x^z} = (x^z)^{(1)/(y)} = x^{(z)/(y)}\\\\\textrm{Using the last one we know:}\\\sqrt[4]{15^7} = 15^(7)/(4)\\\\\textrm{And bonus, not needed in this task:}\\x^y \cdot x^z = x^(y+z)

User Darch
by
4.1k points
11 votes

Answer:

Here,

a = 15. (Base)

b = 7. (Exponents power)

c = 4 (It's fourth root as denominator)

Explanation:

As the form is


{\sqrt[4]{15}}^(7) = {15}^{ (7)/(4) }

User Abhimanyu Daspan
by
3.3k points