Given:
The sequence is
1, 4, 16, 64
To find:
The general term of the given sequence.
Solution:
We have, the sequence
1, 4, 16, 64
Here, the ratio between two consecutive terms is same. So, it is a geometric sequence.
First term is:

Common ratio is:



The nth term of a geometric sequence is
...(i)
Where, a is the first term and r is the common ratio.
Putting a=1 and r=4 in (i), we get


Therefore, the general term of the given sequence is
.