Question

What value of k would give a remainder of 6 when
x2 + kx + 18 is divided by x +4?

Answer 1

k = 7

Explanation:

Given that,

f(x) = x²+kx+18

We need to find the value of k that would give a remainder of 6 when f(x) is divided by (x+4).

We can find it using the remainder theorem.

Taking f(-4) as follows :

f(-4) = (-4)²+k(-4)+18 = 6

16-4k+18=6

16+18-6 = 4k

4k =28

k = 7

So, the value of k is equal to 7.