Question

A construction worker is working on top of a building that is 305m tall. He finishes a pop can and throws it off the top of the building with a velocity of 4.9m/s. Ignoring air resistance, how far did the pop can land from the base of the building?[39m]

Answer 1

Step-by-step explanation:

We do not know because we do not know what the throw angle was.

If we ASSUME a horizontal throw,

time to drop from vertical rest.

t = √(2h/g) = √(2(305)/9.8) = 7.89 s

horizontal distance covered

d = vt = 4.9(7.89) = 38.658... which rounds to 39 m

hopefully his co-workers are under cover as the velocity at ground impact would be 77 m/s or 278 km/hr ... speeds which could cause severe injury or death from the impact of an empty aluminum can. Fortunately real air resistance will reduce the terminal velocity greatly. Still a stunt that would get most workers fired immediately.