Question

In order to get lots of helium into tanks to fill kiddy balloons, they put force or pressure

onto it. If I have 595 liters of helium at 1.00 atmosphere of pressure (that's normal air
pressure, or the pressure of the air), then what volume would it have if I applied 55.0
atmospheres of force or pressure to it? Assume the temperature does not change!

Answer 1

10.8 L

Step-by-step explanation:

Step 1: Given data

• Initial volume of helium (V₁): 595 L

• Initial pressure of helium (P₁): 1.00 atm

• Final volume of helium (V₂): ?

• Final pressure of helium (P₂): 55.0 atm

Step 2: Calculate the final volume of helium

If we assume ideal behavior and constant temperature, we can calculate the final volume of helium using Boyle's law.

P₁ × V₁ = P₂ × V₂

V₂ = P₁ × V₁ / P₂

V₂ = 1.00 atm × 595 L / 55.0 atm = 10.8 L