Answer:
61/121
Explanation:
With replacement, the different outcomes have probabilities ...
P(r, r) = (5/11)(5/11) = 25/121
P(r, b) = (5/11)(6/11) = 30/121
P(b, r) = (6/11)(5/11) = 30/121
P(b, b) = (6/11)(6/11) = 36/121
These outcomes are mutually exclusive, so the probability of any combination of them is the sum of their individual probabilities.
P(x, x) = P(r, r) +P(b, b) = 25/121 +36/121 = 61/121
The probability of two the same color is 61/121.