Question

1200kg car speeds up from 2 m/s to 6 m/s. How many times greater is the car's kinetic

energy at the higher speed compared to the kinetic energy at the slower speed?

Answer 1

9 times as great

Step-by-step explanation:

KE = 1/2mv²

1. 1/2(1200)(2)² = 2,400 J
2. 1/2(1200)(6)² = 21,600 J

21,600 / 2,400 = 9