137k views
10 votes
Write the equation 4 - 3x = -x^2 + 3x in standard form.

Write the equation 4 - 3x = -x^2 + 3x in standard form.-example-1
User Lululu
by
3.6k points

2 Answers

10 votes

Answer:

x^2-3x-3x+5=0

x^2-6x+5=0

a=1, b=-6, c=5

User Paul Bone
by
4.2k points
3 votes

The quadratic equation x^2 - 6x + 4 = 0 can be solved using the quadratic formula, where the coefficients are a = 1, b = -6, and c = 4. The solutions are x = √5 + 3 or x = -√5 + 3.

We can solve the equation using the quadratic formula, which is a general formula for solving quadratic equations.

Rearrange terms:

-3x + 4 = -x^2 + 3x

Move terms to the left side:

-3x + 4 - (-x^2 + 3x) = 0

Distribute:

-3x + 4 + x^2 - 3x = 0

Combine like terms:

x^2 - 6x + 4 = 0

Use the quadratic formula:

Where a, b, and c are the coefficients of the quadratic equation. In this case, a = 1, b = -6, and c = 4. Substituting these values into the formula, we get:

x = (-b ± √(b^2 - 4ac)) / 2a

In this case, a = 1, b = -6, and c = 4. Substituting these values into the formula:

x = (6 ± √((-6)^2 - 4 * 1 * 4)) / (2 * 1)

Separate the equations and simplify:

x = (6 + √20) / 2

x = (6 - √20) / 2

x = √5 + 3 or x = -√5 + 3

The values of a, b, and c that you would use to solve the equation using the Quadratic Formula are:

a = 1

b = -6

c = 4

User Esben Tind
by
3.2k points