Question

Given the following reaction: N2O4(g) yields 2NO2(g). If only 37%of N2O4(g) dissociated, what is the value of the equilibrium constant?

Given: [N2O4] = 1.0M

Answer 1

Kc = 0.22

Step-by-step explanation:

N₂O₄(g) => 2NO₂(g)

C(i) 100% 0%

ΔC -37% +37%

C(eq) 100% - 37% 37%

= 63%

Kc = [NO₂]²/[N₂O₄] = (37%)²/(63%) = (37/100)²/(63/100) = (0.37)²/(0.63) = 0.22