Question

A bakery sold a total of 3028 coffee buns and blueberry buns. 1560 more coffee buns were sold than the blueberry buns. How many coffee buns did the bakery sell?

P.S. No algebra to be used here as it is a grade 4th question!

Answer 1

Given:

Total no. of coffee buns and blueberry buns sold :- 3028

1560 more coffee buns were sold tjan blueberry buns

To find:

The number of coffee buns sold by the bakery

Solution:

Let the number of coffee buns and blue berry buns be x and y respectively..

According to the conditions we can write-

x+y = 3028.. (i)

x-y = 1560.. (ii)

Solving (i) and (ii) we get,

x = 2294

y = 734

The number of coffee buns sold by the Bakery is 2294..

Answer 2

`\large{ \tt{ - \: HEY \: AH~\:♡ }}`

`\large{ \tt{✺ \: SOLUTION}} :`

• Provided : Total sold bakery items : 3028 coffee buns and blueberry buns & 1560 more coffee buns were sold than the blueberry buns.

• To find : Number of coffee buns the bakery sold

- First , Subtract 1560 from 3028 :

`\large{ \tt{→ \: 3028 - 1560 = 1468}}`

We just subtacted the number of more coffee buns from the number of told items sold which means that the number of coffee buns and the number of blueberry buns sold are equal for now. Now divide 1428 by 2 :

`\large{ \tt{→ (1428)/(2) = 734 }}`

Now - Let's get back to the second sentence of the question and add 734 & 1560 :

`\large{ \tt{→ \: 734 + 1560 = \large{ \boxed{2294}}}}`

• Hence , The bakery sold 2294 coffee buns.

- Hope this helps , oneesan! ;)