Question

What is the equation of the line that passes through the point (-6, 6) and has a slope of -5/2?​

Answer 1

y = (-5/2)x - 9

Explanation:

sloped = m = -5/2

point = (x1, y1) = (-6, 6)

using: y - y1 = m(x - x1)

⇒ y - 6 = -5/2(x + 6)

⇒ y - 6 = (-5/2)x - 15

⇒ y = (-5/2)x - 9

Answer 2

`y=-(5)/(2)-9`

Explanation:

The equation of a line (slope-intercept) form is:

y=mx+b

Where m is the slope, b is the y-intercept, and x and y are the x and y coordinates.

We are given the slope and a x,y coordinate pair, therefore we can use those to solve for b, or the y-intercept by plugging in the given values into the equation:

`6=-(5)/(2)*-6+b\\6=(30)/(2)+b\\6=15+b\\`

Subtract 15 from both sides

b=-9

Therefore the equation is:

`y=-(5)/(2)-9`