Question

Given the function evaluate the function at the following points d and e

Answer 1

d).

g(x) = x² +3

g(2t) = (2t)² +3 = 4t²+3

e).

g(x) = x² +3

g(t+1)= (t+1)²+ 3 = t² +2t+1 +3 = t²+2t +4

I hope I helped you^_^