Question

A Los Angeles class nuclear submarine has an internal volume of 1.1x107 liters at a pressure of 1.250 atm. If a crewman were to open one of the hatches to the outside ocean while it was underwater, causing the internal pressure to increase to 5.75 atm, what would be the new volume of the air inside the submarine?

Answer 1

2.39 x 10⁶ Liters

Step-by-step explanation:

Boyle's Law => P₁V₁ = P₂V₂

P₁ = Initial Pressure = 1.250atm P₂ = final pressure = 5.75atm

V₁ = Initial Volume = 1.1 x 10⁷ L V₂ = ? final volume

V₂ = P₁V₁ / P₂ = (1.25atm x 1.1 x 10⁷L)/(5.75atm) = 2.39 x 10⁶ Liters