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Robin has a collection of dimes, nickels and quarters. He has 4 times as many dimes as nickels. He has 20 more quarters than nickels. The

ratio of the number of dimes to the number of quarters is 3:2. Which equation can be used to calculate the number of nickels, n, Robin
has?
OA
Exh
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Robin has a collection of dimes, nickels and quarters. He has 4 times as many dimes-example-1

2 Answers

1 vote

Answer: Robin has 50 nickels, 60 dimes, and 120 quarters.

Explanation:

User Hackerinheels
by
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12 votes

An equation that can be used to calculate the number of nickels, n, Robin has is: A.
(4n)/(n+20) =(3)/(2).

In order to determine the number of dimes, quarters, and nickels, we would assign a variables to the unknown numbers and then translate the word problem into algebraic equation as follows:

  • Let d represent the number of dimes.
  • Let n represent number of nickels.
  • Let q represent number of quarters.

Since Robin has 4 times as many dimes as nickels, an equation that models the situation is given by;

d = 4n

Robin has 20 more quarters than nickels;

q = n + 20

Since the ratio of the number of dimes to the number of quarters is 3:2, we have:

4n/(n + 20)

In this context, an equation that can be used to calculate the number of nickels that Robin has would be written as follows:


(4n)/(n+20) =(3)/(2)

Complete Question:

Robin has a collection of dimes, nickels and quarters. He has 4 times as many dimes as nickels. He has 20 more quarters than nickels. The ratio of the number of dimes to the number of quarters is 3:2. Which equation can be used to calculate the number of nickels, n, Robin has?


(4n)/(n+20) =(3)/(2) \\\\(4n)/(n-20) =(3)/(2) \\\\(n)/(4(n+20)) =(3)/(2) \\\\(n)/(4(n-20)) =(3)/(2)

User Shatema
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5.5k points