Question

Calculate the equivalent molar concentration of sodium hydroxide if the titration of 20,00 ml of 0,05075 M solution of oxalic acid consumed 19,50 ml of this solution.

Answer 1

0.1041 M

Step-by-step explanation:

The reaction that takes place is:

• 2NaOH + H₂C₂O₄ → Na₂C₂O₄ + 2H₂O

First we calculate how many moles of oxalic acid reacted, using the given molarity and concentration:

• 20.00 mL * 0.05075 M = 1.015 mmol H₂C₂O₄

Then we convert H₂C₂O₄ moles to NaOH moles, using the stoichiometric coefficients:

• 1.015 mmol H₂C₂O₄ *
  `(2mmolNaOH)/(1mmolH_2C_2O_4)` = 2.03 mmol NaOH

Finally we calculate the molarity of the NaOH solution:

• 2.03 mmol NaOH / 19.50 mL = 0.1041 M