Question

The sum of two numbers is 58. Twice the second

number subtracted to four times the first number is
28. Find the two numbers.

Answer 1

Explanation:

a+b=58 and 4a-2b=28 is the system of equations

solving the first for a, a=58-b, using this value for b in second equation is

4(58-b)-2b=28

232-4b-2b=28

232-6b=28

-6b=-204

b=34, and since a=58-b

a=58-34

a=24

So the two numbers are 24 and 34