Question

The perimeter of the rectangle is 88 the etive more than twice width find the length and the width​

Answer 1

• L = 88/3 units
• W = 44/3 units

Explanation:

We know that:

• Perimeter of rectangle: 88
• L = 2w

Solution:

• 2(L) + 2(w) = 88 units
• => 2(2w) + 2(w) = 88 units
• => 4w + 2w = 88 units
• => 6w = 88 units
• => w = 88/6 units
• => L = 2w
• => L = 2(14 2/3)
• => L = 2(44/3)
• => L = 88/3 units

Hence, the dimensions of the rectangle is:

• L = 88/3 units
• W = 44/3 units

Answer 2

• Width be x
• Length be 2x

ATQ

`\\ \tt\hookrightarrow Perimeter=88`

`\\ \tt\hookrightarrow 2(x+2x)=88`

`\\ \tt\hookrightarrow 2(3x)=88`

`\\ \tt\hookrightarrow 6x=88`

`\\ \tt\hookrightarrow 3x=44`

`\\ \tt\hookrightarrow x=44/3\approx 15`

• Width=15
• Length=2(15)=30