Answer:
The dimensions of the enlarged rectangle are 6*6.5 cm by 8*6.5 cm, or 39 by 52 cm. The area of this rect. is therefore (39 cm)(52 cm) = 2028 cm^2. The perimeter of the original rectangle is P = 2(6 cm) + 2(8 cm) = 28 cm. The perimeter of the enlarged rectangle is P = 2(39) + 2(48) = 174 cm.
Explanation: