Question

Let
`f(x)` be the function
`(1)/(x+3)`. Then the quotient
`(f(7+h)-f(7))/(h)` can be simplified to
`(-1)/(ah+b)` for:


`a=?`

`b=?`

Answer 1

Explanation:

`(f(7+h)-f(7))/(h)\\=((1)/((7+h)+3)-(1)/(7+3))/(h)\\=((1)/(10+h)-(1)/(10))/(h)\\=((10-(10+h))/(10(10+h)))/(h)\\=(-h)/(10(10+h)h)}\\=(-1)/(10h+100)} \text { for h} \\eq 0`

so a=10, b=100