Question

A 10 kilogram sled is pulled across a frictionless surface with a force of 50 newtons for a distance of 10 meters. The pull is applied to the sled for a time of 2.0 seconds.

Answer 1

The power will be "250 watt". A further explanation is given below.

Step-by-step explanation:

The given values are:

Force,

F = 50 N

Displacement,

d = 20 m

Time,

t = 2.0 seconds

Whenever the block is pulled, the angle will be "0" i.e., Cos0° = 1

Now,

The work will be:

=
`Force* displacement* \Theta`

On substituting the given values, we get

=
`50* 10* Cos0^(\circ)`

=
`50* 10* 1`

=
`500 \ Newton`

Now,

The Power will be:

=
`(Work \ done)/(time)`

=
`(500)/(2.0)`

=
`250 \ watt`