Question

R(-6, 1), S(-3, -3)
Find the coordinates of the midpoint of a segment with given endpoints

Answer 1

`\boxed {\boxed {\sf ( - (9)/(2), -1) \ or \ (-4.5, -1) }}`

Explanation:

We are asked to find the midpoint of a line segment. When you find the midpoint, you essentially find the average of the x-coordinates and the y-coordinates. The midpoint formula is:

`(\frac {x_2+x_1)}{2}, (y_2+y_1)/(2))`

In this formula, (x₁, y₁) and (x₂, y₂) are the endpoints of the line segment. we are given the endpoints R (-6, 1) and S (-3, -3). If we match the value and the corresponding variable we see that:

• x₁= -6
• y₁= 1
• x₂= -3
• y₂= -3

Substitute the values into the formula.

`( (-3 + -6)/(2) , ( 1+ -3)/(2) )`

Solve the numerators.

• -3 + -6 = -9
• 1 + -3 = -2

`(\frac {-9}{2}, \frac {-2}{2})`

Divide.

`( - \frac {9}{2}, -1})`

The fraction can also be written as a decimal.

`(-4.5 , -1)`

The midpoint of the line segment RS is (-9/2, -1) or (-4.5, -1).