Question

You push a 400 kg car for 6 m with a force of 300 N? What is the car’s final speed if all your work became kinetic energy?

Group of answer choices

3 m/s

5.8 m/s

80 m/s

0.40 m/s

Answer 1

3m/s

Step-by-step explanation:

KE = ¹/₂ mv²

But workdone = F x d

Workdone = 300 x 6

Workdone = 1800J

Now per the question.

assuming

workdone= KE

Then

KE = ¹/₂ mv²

1800J = ¹/₂ 400kg x V²

3600J = 400 x V²

3600J / 400kg = V²

9 =V²

V =√(9)

V = 3m/s