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Find the Degree, Leading Term, and Leading Coefficient of this equation.


6j^3+\frac{\sqrt{1(2)/(10) } }{5}

User ACEG
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1 Answer

10 votes

Answer:

the coeficent is 190

Explanation:

I think this right but wait for more people to answer I haven't done this type of math in 3 years trust me it gets better

User Community
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