Question

Morgan is working two summer jobs, making $19 per hour lifeguarding and making $6 per hour walking dogs. In a given week, she can work a maximum of 11 total hours and must earn no less than $120.

Answer 1

Morgan could work 6 hours lifeguarding and 3 hours walking dogs.

Explanation:

the total number of hours worked in both jobs,

x+y

x+y, must be less than or equal to 11

solve inequalities for y

x+y≤11

y≤11−x

Morgan makes $19 per hour lifeguarding, so in x hours she will make

19x dollars. Morgan makes $6 per hour walking dogs, so in

y hours she will make 6y dollars. The total amount earned 19x+6y

19x+6y must be greater than or equal to

$120

solve inequalities for y

19x+6y≥120

6y≥120−19x

y≥20-19/6x

Answer 2

w+d≥14

Explanation:

Here is the full question

Morgan is working two summer jobs, washing cars and walking dogs. She must work no less than 14 hours altogether between both jobs in a given week. Write an inequality that would represent the possible values for the number of hours washing cars, w, and the number of hours walking dogs, d, that Morgan can work in a given week.

Morgan must not work less than 14 hours. This means that the least amount of hours she can work would be 14 hours. This would be represented by the greater to or equal to sign (≥)

So the time she would spend working = w+d≥14

2