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X^2 + X - 12 = 0

In the equation above a is a solution. If a > 0 what must a be equal to?

a: -4
b: 4
c: -3
d: 3

1 Answer

5 votes
x^2+x-12=0

x^2+4x-3x-12=0

x(x+4)-3(x+4)=0

(x+4)(x-3)=0

x+4=0
x-3=0

x=-4
x=3
User Thakur Karthik
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