Question

The function y=h(x) is defined as follows:

h (x) ={x^2 for x<0 ,3-x for 0≤x<1, x^3 for 1≤x≤3, 5 for x>3
h(1)= and h(4)= ​

Answer 1

h(1) = 1

h(4) = 5

Explanation:

Since 1 is in the interval 1 ≤ x ≤ 3, you must substitute 1 into the expression
`x^(3)`

So, h(1) =
`1^(3)` = 1

Since 4 is in the interval x > 3, and all values of x > 3 gives an output of 5, then h(4) = 5