Answer:
Explanation:
Solution by substitution method
3x-4y=8
and 18x-5y=10
Suppose,
3x-4y=8→(1)
and 18x-5y=10→(2)
Taking equation (1), we have
3x-4y=8
⇒3x=4y+8
⇒x=( 4y+8)/ 3 →(3)
Putting x= (4y+8 )/3 in equation (2), we get
18x-5y=10
18( (4y+8) /3) -5y=10
⇒24y+48-5y=10
⇒19y+48=10
⇒19y=10-48
⇒19y= -38
⇒y=- 38 /19
⇒y= -2→(4)
Now, Putting y=-2 in equation (3), we get
x=4y+8
x= (4(-2)+8) /3
⇒x= (-8+8)/ 3
⇒x= 0/ 3
⇒x=0
∴x=0 and y= -2