Question

an oven adds 2260 j heat to a zinc tray that weighs 195g of the tray starts at 25 what is the final temperature of the tray

Answer 1

Divide the grams by 25 to 195 then times it in decimal

Answer 2

Answer: Assuming 25 is 25C, 54.9C

Explanation: The specific heat of zinc is 0.388 J/gC. With 195 grams, we see that for the whole tray, the temperature will change by 1 C for every 75.66J, since (0.388J/gC)*(195g) = 75.66 J/C.

Thus, (2260J)/(75.66J/C) = 29.9 C increase. Add that to 25 to yield 54.9 C (or K, if the 25 was in Kelvin).