Question

) A jeep starts from the state of rest. If its velocity becomes 60 km/hr in 5 minutes, (i) What is the acceleration of the jeep? (ii) What is the distance covered by the jeep? (Ans: 0.056 m/s", 2500 m) ​

Answer 1

Ans: a=0.056ms^-2 S=2500m

Step-by-step explanation:

vi=0ms^-1

vf=60km/hr=
`(60*1000)/(3600)`=16.6ms-1

a=
`(vf-vi)/(t)`

=
`(16.6-o)/(5*60)`

a=0.056ms^-2

S=?

S=vit+
`(1)/(2)`
`at^(2)`

S=0+
`(1)/(2)`*0.056*
`(300)^(2)`

S=2500m