Question

A rectangle's width is one-seventh its length, and its perimeter is 160 m. Find the dimensions of the rectangle.

Answer 1

dimensions of the rectangle is 70m by 10m

Explanation:

w = 1/7 X L

p = 160m

p = 2(L + W)

p = 2( L + L/7)

160/2 = (L + L/7)

80 =( 8L/7)

Make L subject of formula

L = 80 X 7/8

L = 10x 7

L = 70m

W = 1/7 X L

W = 1/7 X 70 = 10m