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Write the quadratic equation in standard form: y=ax^2+bc+c that has the given solutions:

(number 9)

Write the quadratic equation in standard form: y=ax^2+bc+c that has the given solutions-example-1
User Ikkebr
by
8.6k points

2 Answers

3 votes

Answer:

x=-b±√b²-4ac

--------------

2a

User Kapil Thakkar
by
8.5k points
12 votes

Answer:

x² -3x + 1.5

Step-by-step explanation:

Here using the formula:
\left[\begin{array}{ccc}x = ( -b \pm √(b^2 - 4ac))/(2a) \end{array}\right]

we can determine a

2a = 2

a = 1

we can determine b

-b = 3

b = -3

we can determine that b = -3

then using a = 1 , b = -3

find c:

(-3)²-4*1*c = 3

9-4c = 3

-4c = -6

c = 3/2

so the quadratic formula is x² -3x + 1.5

User Pavel Polivka
by
8.3k points

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