Answer:
There are 2 solutions x=0 x=4
Explanation:
2 | 6-3x| +4 = 16
Subtract 4 from each side
2 | 6-3x| +4 -4= 16-4
2 | 6-3x| = 12
Divide by 2
2/2 | 6-3x| = 12/2
| 6-3x| = 6
Now set what is inside the absolute value equal to plus and minus what is on the right side
6-3x = 6 or 6-3x = -6
Subtract 6 from each side
6-6-3x = 6-6 or 6-6-3x = -6-6
-3x =0 -3x = -12
Divide by -3 on each side
-3x/-3 =0/-3 -3x/-3 = -12/-3
x =0 x=4
There are 2 solutions x=0 x=4