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A vertical flagpole, AB, has a height of 46m. The points B, C and D lie on level ground, and BCD is a straight line. Point C is 21 m from the base of the flagpole. The angle of elevation of the top of the flagpole from point D is 58

How far apart are points C and D?

User GeeTransit
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Final answer:

To find the distance between points C and D, we can use trigonometry. Using the tangent function, we can solve for CD. Substituting the given values, we get CD = 54.89m.

Step-by-step explanation:

To find the distance between points C and D, we can use trigonometry. Let CD be the distance between the points. We have the height of the flagpole, AB, which is 46m, and the angle of elevation of the top of the flagpole from point D, which is 58°.



We can use the tangent function in trigonometry to solve for CD.



tan(58°) = AB / CD



CD = AB / tan(58°)



Substituting the values, we have CD = 46m / tan(58°) ≈ 54.89m. Therefore, points C and D are approximately 54.89 meters apart.

User It Grunt
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