Answer:
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Explanation:
x = 7
y = 1
(x-5)² + y² = 5
x-y = 6 then x = y+6
substitute for x:
(y+6-5)² +y = 5
y²+2y+1 +y = 5
reduce:
y²+3y-4 = 0
factor:
(y+4)(y-1) = 0
x = 1+6 = 7
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