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In ΔHIJ, the measure of ∠J=90°, the measure of ∠H=23°, and JH = 2 feet. Find the length of HI to the nearest tenth of a foot.
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In ΔHIJ, the measure of ∠J=90°, the measure of ∠H=23°, and JH = 2 feet. Find the length of HI to the nearest tenth of a foot.

User Ocho
by
7.4k points

2 Answers

8 votes

Answer:

31.5

Explanation:

User Mikemerce
by
7.3k points
9 votes

Answer: 2.2 feet

Explanation:

If your here from delta math that’s the answer

User Justin Holzer
by
7.1k points
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