Question

For a right triangle if a = 11in , c = 15 in find b

Quickkk please help

Answer 1

`\huge\boxed{ \boxed{ \sf{2 √(26) }}}`

Explanation:

to understand this

you need to know about:

• Pythagoras theorem
• PEMDAS

tips and formulas:

• 
  `\sf Pythagoras\: theorem:\\ \sf a²+b²=c²`

given:

• a=11 in
• c=15 in

let's solve:

`\sf step - 1 : make \: b \: the \: subject \: of \: the \: equation`

1. 
   `\sf \: shift \: {a}^(2) \: to \: the\: left \: hand \: side \: and \: change \: its \: sign : \\ \tt {b}^(2) = {c}^(2) - {a}^(2)`
2. 
   `\sf squre \: root \: both \: sides : \\ \tt\sqrt{ {b}^(2) } = \sqrt{ {c}^(2) - {a}^(2) } \\ \tt \: b = \sqrt{ {c}^(2) - {a}^(2) }`

`\sf step - 2 : sustitute \:the \: value \: of \: c \: and \: a \: then \: simplify`

1. 
   `\sf substitute \: the \: given \: value \: of \: c \: and \: b : \\ \tt b = \sqrt{ {15}^(2) - {11}^(2) }`
2. 
   `\sf simplify \: squres : \\ \tt b = √(225 - 121)`
3. 
   `\sf substract : \\ \tt b = √(104)`
4. 
   `\sf simplify \: redica l : \\ \tt b = \sqrt{ {2}^(2) * 26 } \\ \tt \therefore b = 2 √(26)`

Answer 2

The answer to this problem is 2√26

15^2-11^2 = 104
sq root 104