Question

HELP ME FAST THAKS A MILLION PLEASE HELP

Answer 1

b. 15.39 L

Explanation:

Given;

reacting mass of the Nitrogen gas N₂, m = 42 g

pressure of the gas, P = 2 atm

temperature of the gas, T = 250 K

molar mass of Nitrogen, N = 14 g/mol

molar mass of Nitrogen gas N₂, M = 28 g/mol

number of moles of the given Nitrogen gas;

`n = (Reacting \ mass)/(Molar \ mass) = (m)/(M) \\\\n = (42 \ g)/(28 \ g/mol) = 1.5 \ mol.`

The volume occupied by the Nitrogen gas can be calculated from Ideal gas law;

PV = nRT

where;

V is the volume of the gas

R is ideal gas constant = 0.0821 atm.L / mol.K

From the equation above, make V the subject of the formula;

`V = (nRT)/(P) \\\\V = (1.5\ mol. \ * \ 0.0821 \ atm.L/mol.K \ * \ 250 \ K)/(2 \ atm) \\\\V = 15.39 \ L`

Therefore, the volume occupied by the Nitrogen gas is 15.39 L