Answer:
~8.66cm
Explanation:
The length of a diagonal of a rectangular of sides a and b is
![√(a^2+b^2)](https://img.qammunity.org/2022/formulas/mathematics/college/3lrf7ql708ld07oqob3ysz0836uu2lkt3n.png)
in a cube, we can start by computing the diagonal of a rectangular side/wall containing A and then the diagonal of the rectangle formed by that diagonal and the edge leading to A. If the cube has sides a, b and c, we infer that the length is:
![\sqrt{√(a^2+b^2)^2 + c^2} = √(a^2+b^2+c^2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/b4jbhq6ljmvd9fz0xw5gr9st27fybtnbxj.png)
Using this reasoning, we can prove that in a n-dimensional space, the length of the longest diagonal of a hypercube of edge lengths
is
![√(a_1^2 + a_2^2 + a_3^2 + \ldots + a_n^2)](https://img.qammunity.org/2022/formulas/mathematics/high-school/mc2mu47pftppf9zysc2yyc0rm7px6ojdff.png)
So the solution here is
![√((5cm)^2 + (5cm)^2 + (5cm)^2) = √(75cm^2) = 5√(3cm^2) \approx 5\cdot 1.732cm = 8.66cm](https://img.qammunity.org/2022/formulas/mathematics/high-school/onov5xdodwy5oqdpbao27aq02octdsuz84.png)