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CHCl3 has how many double bonds?

User Roland Pish
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2 Answers

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12 votes

Final answer:

CHCl3, also known as chloroform, has no double bonds. It has a tetrahedral geometry with sp³ hybridization, consisting of four single bonds from the central carbon atom to one hydrogen and three chlorine atoms.

Step-by-step explanation:

CHCl3, also known as chloroform, does not have any double bonds. The molecule consists of a single carbon atom bonded to one hydrogen atom and three chlorine atoms. The molecular geometry of chloroform is tetrahedral with sp³ hybridization. This means that the central carbon atom forms four sigma (single) bonds with the surrounding atoms: one to the hydrogen and three to the chlorines, with no remaining p orbitals for pi (double) bonding.

Each chlorine atom in the CHCl3 molecule has seven electrons in its valence shell, participating in forming a single bond with the central carbon atom and at the same time possessing three lone pairs of electrons. The hydrogen atom, having one valence electron, forms a single bond with the carbon atom as well. The carbon atom itself has four valence electrons that are used to form the four single bonds, completing its octet without the need for double bonding.

User Rodrigoap
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13 votes
13 votes

Answer:

It has two sigma bonds ( the single bonds between each H and C) plus one pi bond and one sigma bond that consitute the double bond between C and O. It contains three covalent bonds, one . Hydrogen Bond Donor Count: 0: Computed by Cactvs 3.4.

Step-by-step explanation:

Hope it helps you!

User Aaron J Spetner
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