Question

You are randomly selecting 3 cans of regular and diet cola, but assume that there are 6 cans of regular cola and 7 cans of diet cola.

What is the probability that 2 cans of regular cola and 1 can of diet cola are selected?

Answer 1

Answer:0.367

Explanation:

Given

There are 6 cans of regular and 7 cans of diet cola

number of ways of selecting 2 regular colas and 1 can of diet cola is

`\Rightarrow ^6C_2* ^7C_1`

The total no of ways of selecting 3 items out of 13 items is

`\Rightarrow ^(13)C_3`

Probability is

`\Rightarrow P=(^6C_2* ^7C_1)/(^(13)C_3)=(105)/(286)\\\Rightarrow P=0.367`