Question

Please please help me solve this, I have a test and only 20 mins left T-T
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Answer 1

Answer:
`5.6dm^3[/tex[ of gas is produced when 0.1 moles of magnesium nitrate is decomposed.</strong></p><p><strong>Explanation:</strong></p><p>The balanced chemical equation is: </p><p>[tex]2NH_4NO_3(s)\rightarrow 2MgO(s)+4NO_2(g)+O_2(g)`

According to stoichiometry :

2 moles of
`NH_4NO_3` produce = 4 moles of
`NO_2` gas and 1 mole of
`O_2` gas

2 moles of
`NH_4NO_3` produce = 5 moles of gas

Thus 0.1 mole of
`NH_4NO_3` produce =
`(5)/(2)* 0.1=0.25moles` of gas

Volume of gas produced =
`moles* {\text {Molar volume}}=0.25moles* 22.4dm^3/mol=5.6dm^3`

Thus [tex]5.6dm^3[/tex[ of gas is produced when 0.1 moles of magnesium nitrate is decomposed.